Question

In ABC, point D lies on BC such that AD=AC. prove that AB greater than AC​

Answer 1

Answer:

In triangle ABC, point D lies on BC such that AD=AC then it is proved that AB>AD. Now, from the figure attached below, we can see that ∠ADC is an exterior angle to ΔABD. We know that exterior angle to a triangle is the sum of interior opposite angles of that triangle.