Math, asked by gulnazshaikh1983, 7 hours ago

In ∆ ABC point D on side BC is such that DC = 6, BC = 15.Find A(∆ABD) : A(∆ABC)

5:3
3:5
15:9
None of these​

Answers

Answered by sarikashukla5678
0

Answer:

3:5

Step-by-step explanation:

ΔABC, ΔABDall have same height 'h'.

Base length of ΔABC = 15

Base length of ΔABD = 9

Area of ΔABC= 1/2 × h ×15

Area of ΔABD= 1/2 × h ×9  

A(ΔABD) : A(ΔABC) = (1/2 × h ×9):(1/2 × h ×15) = 3:5

 

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