In ∆ ABC point D on side BC is such that DC = 6, BC = 15.Find A(∆ABD) : A(∆ABC)
5:3
3:5
15:9
None of these
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Answer:
3:5
Step-by-step explanation:
ΔABC, ΔABDall have same height 'h'.
Base length of ΔABC = 15
Base length of ΔABD = 9
Area of ΔABC= 1/2 × h ×15
Area of ΔABD= 1/2 × h ×9
A(ΔABD) : A(ΔABC) = (1/2 × h ×9):(1/2 × h ×15) = 3:5
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