Question

In ∆ABC point D on the side BC is such that DC=8 and BC=13 find A(∆ABC) : A(∆ADB)​

Answer 1

Step-by-step explanation:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴

A(△ABC)

A(△PQR)

=

AB×BC

PQ×QR

=

5×9

6×10

=

3

4