Math, asked by ARMY9394, 6 months ago

In ∆ ABC point P and D are on side AC, hence B is common vertex of ∆ ABD , ∆ BDC , ∆ ABC and ∆ APB and their sides AD, DC, AC and AP are collinear. Heights of all the triangles are equal. Hence, areas of these triangles are proportional to their bases. AC = 16, DC = 9.​

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Answered by kumrbinayjee7750
3

Answer:

In ∆ ABC point P and D are on side AC, hence B is common vertex of ∆ ABD , ∆ BDC , ∆ ABC and ∆ APB and their sides AD, DC, AC and AP are collinear. Heights of all the triangles are equal. Hence, areas of these triangles are proportional to their bases.13

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