In ∆ABC, point p is mid point. of side BC and point or is centroid If AG = 7 then find AP.
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Step-by-step explanation:
'D' is the midpoint of side BC.
'G' is the centroid of
△ ABC.
also given,
to find out,
ar(△ABD)
ar(△AGB)
as 'D' is the midpoint of BC
we get,BD=DC
'G' is the centroid of △ABC.
since we know that,
centroid divides a median in 2:1 ratio
we get,
AG:GD=2:1
as in the given figure ,
the two triangles △ ABD and △AGB
have the same base of line and the
common verier ,so their ratio of
the triangles area will be equal to their
base ratio
so we get,
ar(△ABD)
ar(△AGB)
=
AD
AG
⇒
AG+GD
AG
⇒
2+1
2
⇒
3
2
ar(△ABD)
(△AGB)
=
3
2
solution
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