In ∆ABC , PQ ll BC , AP=12, PB= 8, & AQ= 15 then Find QC.
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Answer:
QC = 10
Step-by-step explanation:
Given
Triangle ABC where PQ ll BC and
AP = 12
PB = 8
AQ = 15
Theorem- If a line is drawn from one side of a triangle parallel to a third side intersection the other side, then the line divides the two sides in equal ratio.
Calculation
The mathematical interpretation of the above theorem with regard to this problem is
Since PQ || BC , AP/PB = AQ/ QC
⇒ 12/8 = 15*QC
⇒ 12QC = 15*8
⇒ QC = 15*8/12
QC = 10
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