Question

in∆ ABC ~ PQR and 4A (∆ABC) =25A(PQR) then AB:PQ=?​

Answer 1

Solution:-

ABC~PQR

4A(∆ABC)=25A(∆PQR)

A(∆ABC) = 25

A(∆PQR) 4

A(∆ABC) = AB²

A(∆PQR) PQ² ..(Theorm of Areas of Similar Triangle)

25 = (AB)²

4 (PQ)²

AB = √25 ..(taking square root)

PQ √4

AB = 5

PQ 2