Question

In ΔABC, ΔPQR and ΔXYZ correspondences ABC⇔ PQR, PQR ⇔ XYZ are similarity. Prove that ABC ⇔ XYZ is similarity.

Answer 1

According to the problem given ,

∆ABC ~ ∆PQR ----( 1 )

∆PQR ~ ∆XYZ ----( 2 )

Therefore ,

∆ABC ~ ∆PQR ~ ∆XYZ

∆ABC ~ ∆XYZ [ transitive property ]

I hope this helps you.

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