Math, asked by 1947splash, 7 months ago

In ΔABC , prove that sin (A+B/2) = cos c/2

Answers

Answered by anandmouli

2

Step-by-step explanation:

A+B+C = 180

A+B = 180-C

(A+B)/2 = 90-C/2

Sin ((A+B)/2) = Sin (90-C/2)

= Cos(C/2)

Hence proved.

Hope you are satisfied with the solution

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