In abc Prove that sin(a+b/2) = cosc/2
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In a triangle
a+b+c= 180°
a+b=180-c
sin(a+b)/2=sin(180-c)/2=sin(90-c/2)=cosc/2
a+b+c= 180°
a+b=180-c
sin(a+b)/2=sin(180-c)/2=sin(90-c/2)=cosc/2
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