In ABC,Q is the midpoint of BC.P
is the midpoint of BQ. Area of ABC
IS 48 sqcm. Find the area of APQ
and ACQ.
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Answer:
Between the triangle ARP and CRQ applying mid point theorem
RP ∥ BC and
RP =
2
1
BC = CQ.
And AR = RC ( R is the mid point of AC )
again PR ∥ BC and AC is the transversal.
Therefore angle ARP = angle RCQ.
Therefore the triangles are congruent by SAS test.
Area ΔARP=AreaΔ RCQ.
By applying the same midpoint theorem we can prove that each of the four triangles have the same area.
So, they divide the triangle into four equal areas.
Now total area = 20 sq. cm.
Therefore area of the Δ PQR is 20 sq.cm divided by 4 = 5 sq.cm
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