in ∆ABC right angled at A. if AB=12cm,AC=5cm find length BC,cot B and cosec C
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Answer:
By using Pythagoras theorem;
AB² + AC² = BC²
12² + 5² = BC²
144 + 25 = BC²
169 = BC²
THEREFORE, BC = 13
cot B = adjacent/opposite
= 12/5
cosec B = hypotenuse/opposite
= 13/5
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