Question

In Δ ABC, right angled at A, if tanC =√3, find the value of SinB.CosC + CosB.SinC​

Answer 1

Answer:

a/q, A=90°, tanC = √3 so C = 60° & B=30°

now,

$\sin(30) \cos(60) + \cos(30) \sin(60) = \sin(30 + 60) = \sin(90) = 1 \: \: \: \: ans$

Answer 2

Answer:

solution in the attachment

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