In ∆ABC, right angled at B,15sinA=12. Find the other
five trigonometric ratios of the angle A
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Given that 15sinA=12, so sinA=1512. Let us consider D ABC (see fig), right angled at B, with BC=12 and AC=15.
By Pythagoras theorem
AC2=AB2+BC2
152=AB2+122
AB2=152−122=225−144=81
∴AB=81=9
We now use the three sides to find the six trigonometric ratios of angle a and c
continued in attachment from here with diagram
THX AND PLS MARK ME AS BRAINLIEST
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