Math, asked by Anonymous, 1 day ago

In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm.

Determine:
(i) sin A, cos A
(ii) sin C, cos C

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Answered by LaRouge
23

Answer:

R.E.F \:  image \\ </p><p></p><p>In Δ ABC, B  \: is \:  at  \: right \:  angle. \\ </p><p></p><p>Given \: , AB=24cm \\ </p><p></p><p>BC=7cm \\ </p><p></p><p>using  \: Pythagoras \:  theorem  \\ </p><p></p><p>AB2+BC2=AC2 \\ </p><p></p><p>⇒(24)2+(7)2=AC2 \\ </p><p></p><p>⇒AC=(242)+(7)2=576+49=625 \\ </p><p></p><p>⇒AC=25CM \\ </p><p></p><p>(i)sin A=ACBC \\ </p><p></p><p>=257 \\ </p><p></p><p>cos A=ACAB \\ </p><p></p><p>=2524 \\ </p><p></p><p>(ii)sin C=ACAB \\ </p><p></p><p>=2524 \\ </p><p></p><p>cos  \: c=ACBC \\ </p><p></p><p>=257    \\ </p><p></p><p>

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