In ABC right angled at B,AB=24 cm, BC =7cm determined (1) sinA, cosA (2) sinC , cos C
Answers
Answered by
1
Answer:
In Δ ABC, right-angled at B
Using Pythagoras theorem
AC² = AB² +BC²
AC² = 576 + 49 = 625
AC = √635
AC = ±25
Now
(i) In a right angle triangle ABC where B=90° ,
Sin A =
=
CosA =
=
(ii) Sin C =
=
Cos C =
=
Step-by-step explanation:
Answered by
1
Answer:
Step-by-step explanation:
In Δ ABC, right-angled at B
Using Pythagoras theorem
AC² = AB² +BC²
AC² = 576 + 49 = 625
AC = √635
AC = ±25
Now
(i) In a right angle triangle ABC where B=90° ,
Sin A =
=
CosA =
=
(ii) Sin C =
=
Cos C =
=
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