Question

In ∆ ABC, right-angled at B AB =5 cm and /_ACB =30° Determine the lengths of the side BC and AC​

Answer 1

Answer:

AC = 10cm

Given:

∠ABC = 90°

∠ACB = 30°

AB = 5cm

To Find:

BC and AC

Solution:

Finding AC

\sf sin30 ^\circ = \dfrac{AB}{AC}sin30

∘

=

AC

AB

\sf \dfrac{1}{2} = \dfrac{5}{AC}

2

1

=

AC

5

AC = 10cm

Finding BC

\sf cos30^ \circ = \dfrac{BC}{AC}cos30

∘

=

AC

BC

\sf\dfrac{\sqrt{3}}{2} = \dfrac{BC}{10}

2

3

=

10

BC

2BC = 10√3

\sf BC = \dfrac{10\sqrt{3}}{2}BC=

2

10

3

BC = 5√3

Answer 2

Answer:

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