in∆ABC, right-angled at B, AB=5 cm and ∆ACB=30°determine the lengths if the sides BC and AC
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Answered by
3
Answer:
Answer:
BC = 5√3cm
AC = 10cm
Given:
∠ABC = 90°
∠ACB = 30°
AB = 5cm
To Find:
BC and AC
Solution:
Finding AC
\sf sin30 ^\circ = \dfrac{AB}{AC}sin30
∘
=
AC
AB
\sf \dfrac{1}{2} = \dfrac{5}{AC}
2
1
=
AC
5
AC = 10cm
Finding BC
\sf cos30^ \circ = \dfrac{BC}{AC}cos30
∘
=
AC
BC
\sf\dfrac{\sqrt{3}}{2} = \dfrac{BC}{10}
2
3
=
10
BC
2BC = 10√3
\sf BC = \dfrac{10\sqrt{3}}{2}BC=
2
10
3
BC = 5√3
Answered by
2
Answer:
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