Question

in ∆ABC, right-angled at B, AB=5cm and angle ACB=30° then the length of the side AC is

Answer 1

AB is 5cm and ACB is 30 degree
sin30 = opposite/ hypotaneus
1/2=5/ AC
therefor AC= 10cm

Answer 2

$\tt\underline\red{Solution}: -$

$\tt{Sin \: 30=\frac{opp \: side}{hyp}}$

$\bf\frac{1}{2} = \frac{AB}{AC}$

$\bf\frac{1}{2} = \frac{5}{AC}$

$\tt\red{AC = 10}$