Question

In ΔABC,right angled at B, AC=13 cm,AB=5 cm  then sinA=​

Answer 1

Answer:

∆ABC-

AC^2=AB^2+BC^2

13^2=5^2+BC^2

BC^2=169-25=144

BC=12 cm

sinA=লম্ব/অতিভূজ=BC/AC=5/13