Math, asked by hemanthkvs99, 5 months ago

In ΔABC,right angled at B, AC=13 cm,AB=5 cm then sinA=

Answers

Answered by Ramyak19

1

Answer:

∆ABC-

AC^2=AB^2+BC^2

13^2=5^2+BC^2

BC^2=169-25=144

BC=12 cm

sinA=লম্ব/অতিভূজ=BC/AC=5/13

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