In ∆abc right angled at b and cosec a = √2, then angle A -angle B
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Answer:
∠A - ∠B = - 45°
Step-by-step explanation:
Given ,
ABC is a right angle triangle and ∠B
cosecA = √2
To Find :-
∠A - ∠B
How To Do :-
As they said that it is right angle at 'B' , we can say that '∠B = 90°'. In the question they gave 'cosecA = √2 ' , We already know that 'cosec45° = √2' so we need to equate the both terms and we need to cancel the term 'cosec' on both sides and we need to find the value of 'A'.
Formula Required :-
cosec45° = √2
Solution :-
cosecA = √2
cosecA = cosec45°
Cancelling 'cosec' on both sides :-
A = 45°
∴ ∠A = 45°
Right angle at 'B' :-
→ ∠B = 90°
∴ ∠A - ∠B :-
= 45° - 90°
= - 45°
∠A - ∠B = - 45°.
Know More :-
1) sinA = 1/cosecA
2) cosA = 1/secA
3) tanA = 1/cotA
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