Question

In ∆abc right angled at b and cosec a = √2, then angle A -angle B​

Answer 1

Answer:

∠A - ∠B = - 45°

Step-by-step explanation:

Given ,

ABC is a right angle triangle and ∠B

cosecA = √2

To Find :-

∠A - ∠B

How To Do :-

As they said that it is right angle at 'B' , we can say that '∠B = 90°'. In the question they gave 'cosecA = √2 ' , We already know that 'cosec45° = √2' so we need to equate the both terms and we need to cancel the term 'cosec' on both sides and we need to find the value of 'A'.

Formula Required :-

cosec45° = √2

Solution :-

cosecA = √2

cosecA = cosec45°

Cancelling 'cosec' on both sides :-

A = 45°

∴ ∠A = 45°

Right angle at 'B' :-

→ ∠B = 90°

∴ ∠A - ∠B :-

= 45° - 90°

= - 45°

∠A - ∠B = - 45°.

Know More :-

1) sinA = 1/cosecA

2) cosA = 1/secA

3) tanA = 1/cotA