Question

In ∆ABC right angled at B, if AB= √3 cm and AC= 2cm, find C and also BC​

Answer 1

using pythagorous theorem in triangle ABC:

$\longmapsto\tt{AC²=AB²+BC²}$

$\longmapsto\tt{BC²=AC²-AB²}$

$\longmapsto\tt{BC²=9-4}$

$\longmapsto\tt{BC=√5}$

Now,

$\longmapsto\tt \: Sin A ={\dfrac{perpendicular}{hypotenuse}}$

$\longmapsto\tt{\dfrac{√5}{3}}$