In ∆ABC right angled at B, if tan A = √3 then the value of cos A cos C-sin A sin C is :
Answers
Answered by
0
Answer:
your answer for the question you ask
Attachments:
Answered by
0
Answer:
0
Step-by-step explanation:
Given, B=90° and tanA=√3 , then A=60°
so, C = 180°-A-B = 180°-60°-90° = 30°
NOW,
cosA.cosC - sinA.sinC = cos(A+C)
= cos(60°+30°) = cos90° = 0.
Similar questions