Question

In △ABC right angled at B, sin C = 5/13.
Find :
(i) sin A
(ii) cos A
(iii) cos C​

Answer 1

Answer:

sin = Perpendicular/Hypotenuse, So P=5 and H=13

Now by PG Theorem

13^2 = 5^2 + Base^2

169=25 + B^2

B = 12

NOW,

1. sin A = Perpendicular(from the perspective of angle A)/ Hypotenuse

            =12/13

2. Cos A = Base/ Hypotenuse = 5/13

3. Cos C= Base (of angle C)/ hypotenuse = 12/13

Step-by-step explanation: