Question

In ΔABC,right angled to B.BD perpendicular to AC.Prove that ΔBDC similar to ΔABC.
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Answer 1

Answer:

In triangle BDC and triangle ABC

BD = BD. ( common)

angle BDC = angle BDA ( both angles are 90°)

CD = AD. ( D is the mid point of AC as BD is perpendicular to AC.

So,

triangle BDC is similar to triangle ABC .

Answer 2

Answer:

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