Question

In ∆ABC, seg AD⊥ side BC. In ∆PQR, seg PS ⊥ side QR. BC =

16, QR = 8, AD = 7 and PS = 5. Find A(∆ABC)

A(∆PQR).

(Nᴏ Kᴏsᴇs Aɴsᴡᴇʀs Aɴᴅ Nᴏ Gᴏᴏɢʟᴇ Aɴsᴡᴇʀs)


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Answer 1

Answer:

area of triangle ABC =56^ CM

area of triangle PQR =20^cm

Step-by-step explanation:

area of triangle ABC =1/2 *b*h

=1/2*16*7

=56^cm

area of triangle PQR =1/2*b*h

=1/2*8*5

=20^cm

note: I've not gooled this answer