Question

In ΔABC seg AP is a median. If BC=18,AB²+AC²=260 Find AP.​

Answer 1

Answer:

AP= 7

Step-by-step explanation:

BP=PC=1/2BC= 9

AB^2+AC^2=2AP^2+2BP^2

260=2AP^2+2(9^2)

260=2AP^2+162

2AP^2=260-162

AP^2=49

AP=7