Question

In ABC seg AP is a median. If BC =18, AB2 + AC2 = 260. find AP

Answer 1

Hello user☺☺

Let the value of AP be x

So,

By generalization, we have

BC^2 = AB^2 + AC^2 + 2AP^2

324 = 260 + 2x^2

x = 32^1/2

So, AP will be 32^1/2

Hope this will help☺