Question

In ΔABC, seg BD bisects ∠ABC.If AB=x,BC=x+5,AD=x–2,DC=x+2, then find the value of x.

Answer 1

x+x-2+x+2+x+5=180
4x+5=180
4x=180-5
×=175/4
x=43.75
x-2+x+2=2x
2×43.75=87.5
x+5=43.75+5=48.75

Answer 2

Answer:

In ΔABC, seg BD bisects ∠ABC.If AB=x,BC=x+5,AD=x–2,DC=x+2,

then  the value of x = 10

Step-by-step explanation:

In ΔABC, seg BD bisects ∠ABC.

AD/DC  = AB/BC

=> (x-2)/(x+2) = x/(x+5)

=> (x-2)(x+5) = x (x+2)

=> x² + 5x - 2x - 10 = x² + 2x

=> 3x - 10 = 2x

=> x = 10

Value of x = 10