Question

in Δ ABC seg BD is perpendicular draw on side AC​

Answer 1

Answer:

Next image is of proof.

Step-by-step explanation:

I hope it helps you.

Answer 2

Answer:

HEY MATE,

→ In triangle ABC, segment BD is perpendicular to the side AC and segment DE is perpendicular to side BC.

→ In ΔBDC and ΔBDE, we have

→ ∠1=∠2 (90°)

→ ∠DBC=∠DBE(Common)

→ Therefore, by AA similarity,

→ ΔBDC ≅ΔBDE,

→By similarity of triangles,

→ BE/BD = BE/ DC

→ BE x BC = BD X DE

→ HENCE PROVED THANK YOU