In ∆ABC, seg DE||side AB, A-D-C &B-E-C, If AD = 5, DC = 3 & BC = 6.4 then find BE.
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In ∆ABC, seg DE || side AB [Given]
∴ DC/AD = EC/BE [Basic proportionality theorem]
∴ 3/4 = (6.4 - x)x
∴ 3x = 5 (6.4 – x)
∴ 3x = 32 – 5x
∴ 8x = 32
∴ x = 32/8 = 4
∴ BE = 4 units .
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