Question

In Δ ABC , seg MN ║ seg BC , if BM = 6 , AN = 5 , AM = 2 , then find NC

Answer 1

In ABC,

MN parallel to BC. (given)

Therefore, by using BPT theorem

AM/MB=AN/NC

=> 2/6=5/NC

=> NC=5*3/2

=> NC=15

Answer 2

Answer:

Step-by-step explanation:

In ∆ABC & ∆AMN

<ABC=<AMN {MN||BC}

<ACB=<ANM{MN||BC}

SO,∆ABC~∆AMN (By AA)

SO,AB/AM=AC/AN

=>6/2=AC/5

=>30/2=AC

=>AC=15

=>CN=AC -- AN = 15 -- 5 = 10