Question

In ABC, segment AP is a median. If BC=18, AB^2+ AC^2=260. Find AP.

Is there any way to solve it without using the 'APPOLONIUS THEOREM'​

Answer 1

Answer:

I think no.

There is no other way .

If it will equilateral triangle then , we can apply pythagoras theorem to find AP median .

Thank you!!

Hope u understood! !

Answer 2

friend

we have to use Pythagoras theorem to proved it but at first we use prove this a equalteral triangle

• angle ABP and angel ACP
• P =P (COMMON)
• ANGLE APB =ANGLE CPA (90 degree each)
• BY AA SIMILARITIES
• TRIANGLE ABP = TRIANGLE ACP

TRIANGLE ABP+TRIANGLE ACP =360 DEGREE

• AB =AC (130 DEGREE each)
• AB +AC+BC=360
• 130 +130+BC=360
• 260+BC=360
• BC=360 - 260
• BC= 100 SOLVED