Question

In ΔABC shown below, AD⊥BC, BE⊥AC and AD=BE. Prove that AE=BD

Answer 1

Answer:

AB//line CD // line EF

CPA = triangle CQB

Answer 2

In ∆AEB and ∆ABD,

Angle ADB = Angle BEA = 90°

AD=BD (Given)

AB=AB (Common)

By RHS rule,

∆AEB (congruent) ∆ABD

By CPCTC,

AE=BD.

Hence Proved.