In ∆ ABC, side AB = AC, if ∠A = 400 , then find other two angles.
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Answer:
55 degree angel
Step-by-step explanation:
Since, AB = AC, therefore, ∠B=∠C
By angle sum property of triangle,
∠A+∠B+∠C=180
o
70
o
+2∠B=180
o
2∠B=110
o
∠B=55
o
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