In ∆ABC, the bisector AD of A is perpendicular to side BC, Show that AB - AC and AABC is isosceles.
(b) In the figure, AB = AC, ZACD: 115, then find angle BAC
Attachments:
Answers
Answered by
0
Answer:
Angle A=50
Step-by-step explanation:
∠ACB + ∠ACD = 180° (Supplementary angles)
∠ACB + 115 = 180 °
∠ACB = 180° - 115°
∠ACB = 65°
∠B = ∠C = 65° (Isosceles triangle property)
IN ΔABC,
∠A + ∠B + ∠C = 180° (Angle Sum Property)
∠A + 65° + 65° = 180°
∠A + 130° = 180°
∠A = 180° - 130°
∠A= 50°
Similar questions