in ∆ABC, the bisector AD of ,angle A is perpendicular to side BC. what triangle is ABC?
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Step-by-step explanation:
Given in ΔABC, the bisector AD of ∠A is perpendicular to side BC.
In ΔBAD and ΔCAD,
∠BAD=∠CAD ....Given
∠ADB=∠ADC=90
AD=AD
∴ΔBAD≅ΔCAD
∴AB=AC .
By converse of isosceles triangle theorem,
∴△ABC is isosceles.
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