In ▲ABC, the bisectors ∠B and ∠C intersect each other at a point D. If ∠BDC = 104°, then the measure of ∠A is :
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Answered by
2
Answer:
we know that
sum of triangle is 180 °
then , ag A + ag B+ ag C = 180°
given , agB+ ag C =104°
agA+agB+ agC = 180°
agA +104° = 180°
ag A = 180° - 104 °
ag A = 76 °
hence prove
I hope this is clear
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Answered by
4
Answer:
28
Step-by-step explanation:
angle BDC =104
angleBDC = 90+angleA/2
104-90=A/2
14=A/2
A=14×2=28
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