In ΔABC, the measure of angle A is equal to the sum of the measures of ∠B and ∠C. Also the ratio of measures of ∠B and ∠C is 4:5. Then find the measures of angles of the triangle.
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Let angle B be 4x and angle C be 5x.
It is also given that angle A = angle B + angle C
therefore angle A = 9x
BTP,
angle A + angle B + angle C = 180
=> 18x = 180
=> x = 10
therefore angle A = 90° ,B = 40° and C = 50 °
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