In abc triangle similar to triangle pqr,if ab/pq=1/3then find ar ∆ABC/ar∆PQR
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rajeswaran:
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Hi ,
It is given that ,
∆ABC ~ ∆ PQR
And AB/PQ = 1/3
( area ∆ABC )/(∆PQR ) = ( AB² )/ ( PQ²)
= ( AB/PQ )²
= ( 1/3 )²
= 1/9
I hope this helps you.
: )
It is given that ,
∆ABC ~ ∆ PQR
And AB/PQ = 1/3
( area ∆ABC )/(∆PQR ) = ( AB² )/ ( PQ²)
= ( AB/PQ )²
= ( 1/3 )²
= 1/9
I hope this helps you.
: )
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