In ABC, X is middle point of AC if XY//AB, then prove that y is middle point of BC
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In ΔCAB, we have XY∥AB, thenCXXA = CYYB [BPT] ........(1)
now, X is the mid point of CA,
then CX = XA.now from (1), we have,
CXCX = CYYB⇒1 = CYYB⇒CY = YB⇒Y is the mid point of BC
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