In ∆ABC, X, Y and Z are the midpoints of AB, BC and CA respectively.
AB: BC: CA = 7:9:10 and XZ = 9 cm, find the perimeter of ∆ABC
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perimeter of triangle is 52 cm
•In traingle ABC & AXY
•Line joining the mid points of two
sides of triangle is parallel to third
side
i.e. XY || BC
•In traingle ABC & AXY
<A = <A
<X = <B ( Corresponding angles)
<Y = <C
traingle ABC is similar to AXY
=> XY/BC = 1/2 ( corresponding
parts of similar triangle)
BC = 18 cm
•Now, let AB = 7x
BC = 9x
CA = 10x
9x = 18
x = 2
AB = 14 cm
BC = 18cm
CA = 20 cm
• perimeter of triangle is 52 cm
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Answer:
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Step-by-step explanation:
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