In ∆ABC,X,Y are midpoints of AB,AC resp and height of ∆ABC is 8cm,XY=6cm. Find the area of ∆ABC.
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2
Answer:
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Answered by
10
Step-by-step explanation:
48 cm
are of triangle=1/2*base*height by mid point theorem the length of the
here height=8cm
two mid points of two sides is half of the third side and parallel to this side
therefore,
XY=1/2(BC)
2(6)=BC
12=BC
we got height and base value also now
find the area
area=1/2*12*8
area=48 cm
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