In ABCD, as compared to the
measure of A, the measure of
B exceeds by 10°. the measure
of C exceeds by 20° and the
measure of D exceeds by 10°
Find the measure of all the angles
of ABCD
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angle A+angle B+angle C+angle D=360°
angle A+10°=angle B
angle A+20°=angle C
angle A+10°=angle D
So, A+ A+10°+ A+20°+ A+10°=360°
= 4A+40°=360°
=4A=360-40
=4A=320
A=320/4
A=80°
B=80°+10°=90°
C=80°+20°=100°
D=80°+10°=90°
The measure of all the angles of ABCD are 80°, 90°, 100° and 90° respectively
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Step-by-step explanation:
In ABCD, as compared to the
measure of A, the measure of
B exceeds by 10°. the measure
of C exceeds by 20° and the
measure of D exceeds by 10°
Find the measure of all the angles
of ABCD
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