Question

In ABCD,BCparallel to AD diagonals AC and BD intersect each other at point p if AP =1/3 AC,then prove that DP=1/2BP
​

Answer 1

Answer:

Clearly, △APD∼△CPB

⇒

CP

AP

=

PB

PD

⇒

AC−AP

AP

=

PB

PD

⇒

AP

AC

−1

1

=

PB

PD

⇒

3−1

1

=

PB

PD

∴ DP=

2

1

BP