In ΔABCD, P, Q and R are the midpoint of AB, BC, and CA respectively if AB=12cm,BC=16 cm and CA =20 cm, find the perimeter of trapezium PBCR.
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P AND R ARE THE MID POINT SIDE AB AND AC RESPECTIVELY.
BY MID POINT THEOREM
PR = 1/2BC ,PR||BC
PR = 1/2 ×16
=>PR = 8CM
PB =1/2 AB AND RC =1/2AC ( P AND R MID POINT OF THE SIDES AB AND AC RESPECTIVELY. )
=>PB =1/2×12 AND RC =1/2×20
=>PB =6 AND RC =10
HENCE ,PERIMETER TRAPEZIUM = SUM OF ALL SIDES
=>6+10+16+8
=> 40CM
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