Question

In □ ABCD , side BC|| side AD. seg AC And seg BD intersect in point Q if AQ =1/3 AC Then show that DQ = 1/2 BQ.​

Answer 1

Step-by-step explanation:

step by step explanation is in the attachment ☺️

Answer 2

DQ = BQ/2  in in quadrilateral ABCD side BC|| side AD. seg AC And seg BD intersect in point Q if AQ =1/3 AC

Step-by-step explanation:

side BC|| side AD

seg AC And seg BD intersect in point Q

=> ∠ADQ = ∠CBQ

    ∠DAQ  = ∠BCQ

    ∠DQA  = ∠BQC  ( opposite angle)

=> ∠DQA  ≈∠BQC  

=> DQ/BQ  = AQ/CQ

AQ = AC/3

=> AC = 3AQ

CQ = AC - AQ = 3AQ - AQ = 2AQ

=> DQ/BQ  = AQ/2AQ

=> DQ/BQ  = 1/2

=> DQ = BQ/2

QED

Proved

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