Question

In above fig. ∆ABC is inscribed in a circle with centre O.if BAC =x+13° and ACB =3x-7°
the value of x is​

Answer 1

Answer:

We know that angle inscribed in a semicircle is 90 degree

Thus.. ABC=90degree

Step-by-step explanation:

Now,

In triangle ABC applying angle sum property

ABC+BAC+BCA = 180 degree

90+BAC+ BCA =180

BAC + BCA= 90

x+13+3x-7=90

4x+6=90

4x=84

x=84/4

x=21 degree

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