Question

In ACB, C = 90°, AC-3, BC=4. Find the ratio of sinA,cosA,tanB,solve by Pythagoras theorem​

Answer 1

Step-by-step explanation:

ΔACB is right angled triangle.

angle C=90°

by Pythagoras therom,

(AB)²=(AC) ²+(BC) ²

(AB)² =(3)²+(4)²

(AB)² =9+16

(AB)² =25

AB =5

sinA=AB/AC

=5/3

cosA=BC/AC

=4/3

tanB=AB/BC

=5/4

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Answer 2

Answer:

AC=3

BC==4

AB=5

BY PYTHAGORAS THEOREM

AB=5

IN ∆ABC TEETA ANGLE A then

P=BC

H=AB

B=AC

sinA= p/h =BC/AB=4/5

cosA =b/h=AC/AB=3/4

when teeta angle B then,

P=AC

H=AB

B=BC

then,tanB=p/b=ac/bc

tanB =3/5