Question

In accordance with the Bohr’s model, find the quantum number that characterises the earth’s revolution around the sun in an orbit of radius 1.5 × 1011 m with orbital speed 3 × 104 m/s. (Mass of earth = 6.0 × 1024 kg.)

hi ellarum enna doing

Answer 1

$\fbox\red{αвѕωєя}$

rαdíuѕ σf thє σrвít σf thє єαrth αrσund thє ѕun,

r = 1.5 × 1011 m

σrвítαl ѕpєєd σf thє єαrth,

ν = 3 × 104 m/ѕ

mαѕѕ σf thє єαrth,

m = 6.0 × 1024 kg

αccσrdíng tσ вσhr’ѕ mσdєl, αngulαr mσmєntum íѕ quαntízєd αnd gívєn αѕ:

mvr = nh/2π

whєrє,

h = plαnck’ѕ cσnѕtαnt = 6.62 × 10−34 jѕ

n = quαntum numвєr

∴ n = mvr2π/h

= (2πх6х1024х3х104х1.5х1011)/(6.62х10-34)

= 25.61х1073 = 2.6 х 1074

hєncє, thє quαntα numвєr thαt chαrαctєrízєѕ thє єαrth’ rєvσlutíσn íѕ 2.6 × 1074 .

Answer 2

Answer:

oooh thats great...fine

rithu akka 10th board la evlo marks nu kettu sollu?